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What is the range of the equation y 4x2 - 8?
y > -8
Which equation can have the following domain and range?
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
What is the domain and range of y equals 2x plus 8?
The domain and range of the equation y = 2x+8 are both [-infinity,+infinity].
How do you solve this equation for x - y equals x - x2?
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
Is x2 plus 8 a function?
x2+8= y This equation represents a function. It will be a parabola with the vertex at (0,8). You can easily graph this on a graphing calculator or from prior knowledge. You know the basic graph of y=x2 with vertex (0,0) and opens upwards on the y-axis. From the equation, you simply shift the vertex vertically up 8 so the new vertex is (0,8) This represents a function because for every x value there is one y value.
What is the range of the equation y 4x2 - 8?
y > -8
Is y equals x2 a nonlinear equation?
If you mean y = x2, then yes, it is nonlinear.
Which equation can have the following domain and range?
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
An equation of the axis of symmetry of the graph y equals -x2 plus 8x-7?
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4
How do you prove that the line y equals x-4 is tangent to the curve of x squared plus y squared equals 8?
equation 1: y = x-4 => y2 = x2-8x+16 when both sides are squared equation 2: x2+y2 = 8 Substitute equation 1 into equation 2: x2+x2-8x+16 = 8 => 2x2-8x+8 = 0 If the discriminant of the above quadratic equation is zero then this is proof that the line is tangent to the curve: The discriminant: b2-4ac = (-8)2-4*2*8 = 0 Therefore the discriminant is equal to zero thus proving that the line is tangent to the curve.
What is the domain and range of y equals 2x plus 8?
The domain and range of the equation y = 2x+8 are both [-infinity,+infinity].
How do you solve this equation for x - y equals x - x2?
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
The circle is centered at the origin and the length of its radius is 8 What is the circle's equation?
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
Is x2 plus 8 a function?
x2+8= y This equation represents a function. It will be a parabola with the vertex at (0,8). You can easily graph this on a graphing calculator or from prior knowledge. You know the basic graph of y=x2 with vertex (0,0) and opens upwards on the y-axis. From the equation, you simply shift the vertex vertically up 8 so the new vertex is (0,8) This represents a function because for every x value there is one y value.
Is y x2 7 OR y x'squared' 7 a linear equation?
no..
What is the line of symmetry for the parabola whose equation is y x2 - 12x 7?
y=x2-12x+7
What is the absolute extrema of X2 plus 16X-4?
y = x2 + 16x - 4The minimum value of y in this case is -b/2a, or -16/2, which is -8. If you solve the equation for x = -8, you will find the coordinates of the lowest point are (-8, -68).
