y = 2x2 + 4x - 3
This equation describes a parabola. Because it's first term is positive, we know that it goes infinitely upward, and has a minimum that occurs at it's vertex. You can find it's vertex by taking it's derivative and solving for zero:
y' = 4x + 4
0 = 4x + 4
0 = x + 1
x = -1
y = (-1)2 + 4(-1) - 3
y = 1 - 4 - 3
y = -6
So the vertex is at (-1, -6), which means that y ≥ -6
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4x3+10x2+2x+5= (2x+5)(2x2+1)
14
4x3=12 250-12=238 238/50=4.76
4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)
12 divided by 3 equals 4. Then, 4 times 3 equals 12. Finally, 4 plus 12 equals 16.