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How do you find the rate of change for 5x plus 3y equals -2?
Rearrange for y, let f(x) = y, and find the derivative of f(x) with respect to x: 5x + 3y = -2 y = -(5x+2)/3 = f(x) df/dx = -5/3
What is the slope of 5x-y plus 3 equals 0?
5x - y + 3 = 0can be rewritten as y = 5x + 3 and so the slope is the coefficient of x which is 5.
What is the equation y equals 5x-3 telling you?
8
What is the solution of x if -5x equals 3 plus y?
-5x=3+y x=-1/5y-3/5
What is the rate of change for the linear function y equals 2x plus 3?
The rate of change for the linear (not liner) function, y = 2x +/- 3 is 2.
What is the rate of change in a linear relationship?
The rate of change equals the slope. In the basic formula y=mx+b, the rate of change is equal to m. In the equation y=5x+3, the rate of change equals 5.
How do you find the rate of change for 5x plus 3y equals -2?
Rearrange for y, let f(x) = y, and find the derivative of f(x) with respect to x: 5x + 3y = -2 y = -(5x+2)/3 = f(x) df/dx = -5/3
What is the slope of 5x-y plus 3 equals 0?
5x - y + 3 = 0can be rewritten as y = 5x + 3 and so the slope is the coefficient of x which is 5.
What is the equation y equals 5x-3 telling you?
8
What is the rate of change if y equals -3 plus 10?
If 'y' equals 3 plus 10, then 'y' equals 13 ... today, tonight, and tomorrow, until the cows come home, pigs fly, and hell freezes over. 'Y' does not change, so its rate of change is zero.
What is the slope of a line that is parallel to y 5x 3?
It has the same slope as the line in the question. If a line has equation y = mx + c, its slope is m. If the line in question is y = 5x + 3, the slope of a parallel line is 5; If the line in question is y + 5x = 3 → y = -5x + 3 (subtract 5x from both sides), the slope of a parallel line is -5.
What is the solution of x if -5x equals 3 plus y?
-5x=3+y x=-1/5y-3/5
What is the rate of change for the linear function y equals 2x plus 3?
The rate of change for the linear (not liner) function, y = 2x +/- 3 is 2.
What is 4x 5x-y?
Alright this is not very well put, so I have three possible equations that I can think of on the fly. I will attempt to answer all three.1) (4)5x-y=+y +y(4)5x=y/4 /45x=y/4/5 /5[x=(y/4)/5]2) (4x)5x-y=20x2-y=+y +y20x2=y/20 /20[x2=y/20]3) 4x=5x-y+y +y4x+y=5x-4x -4x[y=x]1) (4)5x-y=+y +y[20x=y]2) (4x)5x-y=20x2-y=+y +y[20x2=y]3) 4x=5x-y+y +y4x+y=5x-4x -4x[y=x]
Are there any solutions to these inequalities y-5x plus 2 and y-5x-3?
No, there are not, and here's why: to solve for this kind of problem, you will need to set both equations equal to each other. This will give you y - 5x + 2 = y - 5x - 3, You can subtract a y and a -5x from both sides, and this will leave you with 2 = -3, which is, of course, an impossibility. There are therefore no solutions to these inequalities.
What is the point of contact when y equals 5x meets y equals 3 -x on the Cartesian plane showing work?
If: y = 5x and y = 3 -x Then: 5x = 3 -x => 5x +x = 3 => 6x = 3 => x = 1/2 By substitution point of contact is at: (1/2, 5/2)
What is the substitution method for y equals 5x plus 8 and y equals 10x plus 3?
5x+8 = 10x+35x-10x = 3-8-5x = -5x = 1 and by substituting the value of x into the equations y = 13
