That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
24
To find the value of ( x ), we can set up an equation using the given relationships. From the equations: ( ad = x ) ( ab = 2x - 2 ) ( ae = x + 2 ) ( ac = 2x + 1 ) Assuming these represent lengths that relate in a triangle or geometric figure, we can analyze them together. Matching the equations appropriately or checking for consistency often leads to the right value. Solving the system, we find that ( x = 2 ).
The question cannot be answered since it is inconsistent. It first states that AB equals 5 cm and then AB equals 6 cm. Please check your typing and resubmit.
x = 0.125 ( BC - 7 )
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
a(b + d).
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
If abcd is a parallelogram, then the lengths ab and ad are sufficient. The perimeter is 36 units.
Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
9
14
24
Double-replacement
Isosceles trapezoid ABCD has an area of 276 If AD = 13 inches and DE = 12 inches, find AB.
28.00
For you A+ Cheaters ;D it's 50!