None, other than that if the area is x square units, the perimeter must be greater than or equal to 4*sqrt(x) units. It is possible to construct a rectangle for each and every one of the infinitely many values greater than 4*sqrt(x) units. Consequently, there can be no relationship as suggested by the question.
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That depends on the rectangle! You can have different rectangles with the same area, but with different perimeters.
Not enough data. Different rectangles (different length:width ratios) can have the same area, but different perimeters.
The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.
There is no simple relationship between area and perimeter. For the same area, you can have different perimeters, depending on whether the enclosed area is a square, a 2:1 rectangle, a 3:1 rectangle, etc., a circle, a 2:1 ellipse, a regular pentagon, etc.
Infinitely many. Suppose the area of the rectangle is 100. We could create rectangles of different areas: 100x1 50x2 25x4 20x5 10x10 However, the side lengths need not be integers, which is why we can create infinitely many rectangles. Generally, if A is the area of the rectangle, and L, L/A are its dimensions, then the amount 2(L + (L/A)) can range from a given amount (min. occurs at L = sqrt(A), perimeter = 4sqrt(A)) to infinity.