None, other than that if the area is x square units, the perimeter must be greater than or equal to 4*sqrt(x) units. It is possible to construct a rectangle for each and every one of the infinitely many values greater than 4*sqrt(x) units. Consequently, there can be no relationship as suggested by the question.
That depends on the rectangle! You can have different rectangles with the same area, but with different perimeters.
Not enough data. Different rectangles (different length:width ratios) can have the same area, but different perimeters.
The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.
There is no simple relationship between area and perimeter. For the same area, you can have different perimeters, depending on whether the enclosed area is a square, a 2:1 rectangle, a 3:1 rectangle, etc., a circle, a 2:1 ellipse, a regular pentagon, etc.
Infinitely many. Suppose the area of the rectangle is 100. We could create rectangles of different areas: 100x1 50x2 25x4 20x5 10x10 However, the side lengths need not be integers, which is why we can create infinitely many rectangles. Generally, if A is the area of the rectangle, and L, L/A are its dimensions, then the amount 2(L + (L/A)) can range from a given amount (min. occurs at L = sqrt(A), perimeter = 4sqrt(A)) to infinity.
There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.
That depends on the rectangle! You can have different rectangles with the same area, but with different perimeters.
Not enough data. Different rectangles (different length:width ratios) can have the same area, but different perimeters.
The relationship between the length and width of rectangles with the same area means that if you decrease one dimension, you must increase the other to maintain the same area. This relationship is described by the formula for the area of a rectangle: Area = length x width. Changing the length and width proportionally maintains the overall area constant.
The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.The perimeter for a certain area varies, depending on the figure. For example, a circle, different ellipses, a square, different rectangles, and different shapes of triangles, all have different perimeters or circumferences, for the same area.
No, in general that is not true. For two similar figures it is true. But you can easily design two different figures that have the same perimeters and different areas, or the same area and different perimeters. For example, two rectangles with a different length-to-width ratio.
There is no standard relationship between perimeter and area. For example, you can have two rectangles that have the same perimeter, but different area.
You can't tell. The perimeter doesn't tell you the area. There are an infinitenumber of different rectangles, with different dimensions and different areas,that all have perimeters of 56.The greatest area it can have is 196 cm2 ... if it's a square with 14-cm sides.If it's not a square, then it can have any area less than 196 cm2.Here are a few rectangles. They all have perimeters of 56:1 x 27, area = 272 x 26, area = 523 x 25, area = 754 x 24, area = 965 x 23, area = 11510 x 18, area = 18013 x 15, area = 195
There is no simple relationship between area and perimeter. For the same area, you can have different perimeters, depending on whether the enclosed area is a square, a 2:1 rectangle, a 3:1 rectangle, etc., a circle, a 2:1 ellipse, a regular pentagon, etc.
It's very easy for two rectangles to have the same area and different perimeters,or the same perimeter and different areas. In either case, it would be obvious toyou when you see them that there's something different about them, and theywould not fit one on top of the other.But if two rectangles have the same area and the same perimeter, then to look at themyou'd swear that they're the same rectangle, and one could be laid down on the otherand fit exactly.
Infinitely many. Suppose the area of the rectangle is 100. We could create rectangles of different areas: 100x1 50x2 25x4 20x5 10x10 However, the side lengths need not be integers, which is why we can create infinitely many rectangles. Generally, if A is the area of the rectangle, and L, L/A are its dimensions, then the amount 2(L + (L/A)) can range from a given amount (min. occurs at L = sqrt(A), perimeter = 4sqrt(A)) to infinity.
When rectangles are inscribed, they lie entirely inside the area you're calculating. They never cross over the curve that bounds the area. Circumscribed rectangles cross over the curve and lie partially outside of the area. Circumscribed rectangles always yield a larger area than inscribed rectangles.