Divide the number by 5, and the remainder in that division is the 'ones' (50) digit. Take that quotient (without the remainder) and divide by 5. The remainder is the 'fives' (51) digit. Continue dividing until you have zero, with a remainder and that will be the leftmost digit. Example 27 (base ten) to base 5: 27 / 5 = 5, remainder 2 5 / 5 = 1, remainder 0 1 / 5 = 0, remainder 1 so 102 (base 5) is the same as 27 (base 10). You can check: 1 is in the (52=25) place, and the 2 is in the 'ones' place. So (1*25) + (0*5) + (2*1) = 27
Your question's meaning eludes me. You can divide any number by 5, whether or not it is a remainder, and why would you want to divide a remainder by 5 anyway?
5.4
27 divided by 5 is 5 with remainder 2
It is: 5678/27 = 210 with a remainder of 8
Divide the number by 5, and the remainder in that division is the 'ones' (50) digit. Take that quotient (without the remainder) and divide by 5. The remainder is the 'fives' (51) digit. Continue dividing until you have zero, with a remainder and that will be the leftmost digit. Example 27 (base ten) to base 5: 27 / 5 = 5, remainder 2 5 / 5 = 1, remainder 0 1 / 5 = 0, remainder 1 so 102 (base 5) is the same as 27 (base 10). You can check: 1 is in the (52=25) place, and the 2 is in the 'ones' place. So (1*25) + (0*5) + (2*1) = 27
Yes, you can have a remainder of 5 when you divide by 6. If you divide 11 by 6, it will go into it one time with a remainder of 5.
There is no remainder because 189540/27 is exactly 7020
27
Your question's meaning eludes me. You can divide any number by 5, whether or not it is a remainder, and why would you want to divide a remainder by 5 anyway?
5.4
27 divided by 5 is 5 with remainder 2
26. This is because when you divide 26 by 5, you have a remainder of 1, and when you divide it by 4, you have a remainder of 2
122.2381
you can do divide 83 and 5 and that will be your biggest remainder.
When you divide by 5, the remainder can be 0, 1, 2, 3, or 4, but no more than 4.
32 divided by 5 is 6 with remainder 2.