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2,1,0 is th sequence of its terms
5, 8, 11, 14 and 17.
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
The way of asking the question is wrong. It is known as common difference not common ratio. Here a = 1 , d= 3 a7=? we know that , an = a + (n-1)d a7= 1 +6x3= 19
If the first term is 12 and the seventh term is 36, then we have gone up 36-12 in the space of 6 term changes. This is 24 per 6 changes, which can be written as the division 24/6. This works out as 4. Thus the common difference in the sequence is 4.
2,1,0 is th sequence of its terms
5, 8, 11, 14 and 17.
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
The way of asking the question is wrong. It is known as common difference not common ratio. Here a = 1 , d= 3 a7=? we know that , an = a + (n-1)d a7= 1 +6x3= 19
To find the seventh term in the sequence -6, -11, -16, -21, -26, we first identify the pattern: each term decreases by 5. Therefore, the next term would be -26 - 5 = -31. Continuing this pattern, the seventh term would be -31 - 5 = -36.
If the first term is 12 and the seventh term is 36, then we have gone up 36-12 in the space of 6 term changes. This is 24 per 6 changes, which can be written as the division 24/6. This works out as 4. Thus the common difference in the sequence is 4.
The question does not contain a sequence but a single large number whose digits are the digits of the sequence, 3n run together. There is only one number, not a sequence, so there is no nth term.
Yes, it can.
1 - 2 - 4 - 8 - 16 - 32 - 64 the sequence doubles
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