-1
2,1,0 is th sequence of its terms
5, 8, 11, 14 and 17.
To find the seventh term of a sequence, you need to identify the pattern or formula governing the sequence. If it's an arithmetic sequence, you can use the formula ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term, ( d ) is the common difference, and ( n ) is the term number. For a geometric sequence, use ( a_n = a_1 \cdot r^{(n-1)} ), where ( r ) is the common ratio. Substitute ( n = 7 ) into the appropriate formula to find the seventh term.
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
The way of asking the question is wrong. It is known as common difference not common ratio. Here a = 1 , d= 3 a7=? we know that , an = a + (n-1)d a7= 1 +6x3= 19
2,1,0 is th sequence of its terms
5, 8, 11, 14 and 17.
To find the seventh term of a sequence, you need to identify the pattern or formula governing the sequence. If it's an arithmetic sequence, you can use the formula ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term, ( d ) is the common difference, and ( n ) is the term number. For a geometric sequence, use ( a_n = a_1 \cdot r^{(n-1)} ), where ( r ) is the common ratio. Substitute ( n = 7 ) into the appropriate formula to find the seventh term.
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
The way of asking the question is wrong. It is known as common difference not common ratio. Here a = 1 , d= 3 a7=? we know that , an = a + (n-1)d a7= 1 +6x3= 19
To find the seventh term in the sequence -6, -11, -16, -21, -26, we first identify the pattern: each term decreases by 5. Therefore, the next term would be -26 - 5 = -31. Continuing this pattern, the seventh term would be -31 - 5 = -36.
If the first term is 12 and the seventh term is 36, then we have gone up 36-12 in the space of 6 term changes. This is 24 per 6 changes, which can be written as the division 24/6. This works out as 4. Thus the common difference in the sequence is 4.
The question does not contain a sequence but a single large number whose digits are the digits of the sequence, 3n run together. There is only one number, not a sequence, so there is no nth term.
Yes, it can.
In a geometric sequence, the ratio between consecutive terms is constant. Given that the sixth term is 18 and the eighth term is 32, we can find the common ratio ( r ) by dividing the eighth term by the sixth term: ( r = \frac{32}{18} = \frac{16}{9} ). To find the seventh term, we can multiply the sixth term by the common ratio: ( 18 \times \frac{16}{9} = 32 ). Therefore, the seventh term is 32.
1 - 2 - 4 - 8 - 16 - 32 - 64 the sequence doubles