-3
2x2-6x+2y+18 = 0. Subtract the 2y from both sides. 2x2-6x+18 = -2y. Divide all by -2 to get y by itself. -x2+3x-9 = y. This graph is going to be a parabola that opens downward, like a frown.
3y - 37 = 2x2 - 18x3y = 2x2 - 18x + 37y = (2/3)x2 - 6x + (37/3)The graph is a parabola.Shanice outshines Manuel.
I don't understand your question but y=3x is the function of a graph, to graph the function you would plug points into the function such as x=0, x=1, x=-1 and you would find the y values at each point so that you can graph it. In this case the graph is a parabola which has a u shape.
no
-3
y=-2x^2+8x+3
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2x2-6x+2y+18 = 0. Subtract the 2y from both sides. 2x2-6x+18 = -2y. Divide all by -2 to get y by itself. -x2+3x-9 = y. This graph is going to be a parabola that opens downward, like a frown.
3y - 37 = 2x2 - 18x3y = 2x2 - 18x + 37y = (2/3)x2 - 6x + (37/3)The graph is a parabola.Shanice outshines Manuel.
y
y = 2x2 - 3x + 1 y = (x - 1)(2x - 1) x - 1 = 0 2x - 1 = 0 x = 1 x = 1/2 the answer is 2
The graph is a straight line. It crosses the y-axis at y=-9/7 , and its slope is 1426/7 .
2x2= 4
Most "quartic" functions will give you a M- or a w- shaped graph. Try y = x^4 -4x^2 for a W-shape, and y = -x^4 + 4x^2 for a M-shape.
You need to define a domain: the set of values that x can take.Then, for each of a selection of value of x, calculate the value of y = 2x2-7x-15. Plot the point (x, y) on a coordinate plane. Finally, join the plotted points using a smooth curve.
I don't understand your question but y=3x is the function of a graph, to graph the function you would plug points into the function such as x=0, x=1, x=-1 and you would find the y values at each point so that you can graph it. In this case the graph is a parabola which has a u shape.