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Write the equation in slope intercept form of the line that contains the points4 -7 and 0 5?
slope-intercept form: y = mx + b, where m = slope, b = y-intercept.Let (x1, y1) = (0, 5) and (x2, y2) = (4, -7)1. Finf the slope m.m = (y2 - y1)/(x2 - x1) = (-7 - 5)/(4 - 0) = -12/4 = -32. Use the slope -3 and the point (0, 5) to write the point-slope form of the equation of the line, then reduce it to the slope-intercept form.(y - y1) = m(x - x1) (substitute 5 for y1, -3 for m, and 0 for x1)y - 5 = -3(x - 0)y - 5 = -3x (add 5 to both sides)y = -3x + 5
What is the slope-intercept form of the linear equation 2x and ndash8y32?
The browser used for posting questions on this site is rubbish. It is quite useless for mathematics since it strips out most symbols so that we cannot tell what the question is meant to be. Here, all that I can see of the equation is "2x and ndash8y32" : no equals sign! I am assuming that you meant 2x - 8y = 32.The slope intercept form is y = 1/4*x - 4
What is the slope of the line that contains the points -32 23 and -32 -19?
It has no slope.
Two points to point slope form?
Let : A ≡ ( x1, y1 ) ≡ ( 4, - 4), B ≡ ( x2, y2 ) ≡ ( 9, -1 ).Then, slope of line AB ism = ( y₂ - y₁ ) / ( x₂ - x₁ ) = (-1 + 4 ) / ( 9 - 4 ) = 3/5Hence, equation of line AB in Point-Slope Form isy - y₁ = m ( x - x₁ )y + 4 = (3/5) ( x - 4 ) .................... (1)5y + 20 = 3x - 125y = 3x - 32y = (3/5)x + (-32/5) ....................... (2)This is the Slope-Intercept Formy = mx + b.The form which is easier to get isSlope-Point Form. But this is one'spersonal choice.
What is the slope of (-25) and (-57)?
32
