slope-intercept form: y = mx + b, where m = slope, b = y-intercept.
Let (x1, y1) = (0, 5) and (x2, y2) = (4, -7)
1. Finf the slope m.
m = (y2 - y1)/(x2 - x1) = (-7 - 5)/(4 - 0) = -12/4 = -3
2. Use the slope -3 and the point (0, 5) to write the point-slope form of the equation of the line, then reduce it to the slope-intercept form.
(y - y1) = m(x - x1) (substitute 5 for y1, -3 for m, and 0 for x1)
y - 5 = -3(x - 0)
y - 5 = -3x (add 5 to both sides)
y = -3x + 5
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
Y=mc+b
As for example if the slope is 3 and the y intercept is 6 then the equation is: y=3x+6
It is: y-7 = 2(x-3) => y = 2x+1
As a straight line equation: y = -3x+18 in slope intercept form
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
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The answe iss..... 6
y = 2x - 1
It is: y = 2x-6
y=2x+1
y= slope + y-intercept
y-9 = 3(x-4) y = 3x-3 in slope intercept form
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
Y=mc+b
4