To find the slope-intercept form (y = mx + b) of the line passing through the points (2, 11) and (4, 17), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{17 - 11}{4 - 2} = \frac{6}{2} = 3 ). Next, we can use one of the points to find the y-intercept (b). Using the point (2, 11): ( 11 = 3(2) + b ) gives ( b = 5 ). Thus, the slope-intercept form is ( y = 3x + 5 ).
The origin and infinitely many other points of the form (x, ax) where x is any real number.
The equation for the given points is y = x+4 in slope intercept form
Slope=8 point=(-7,3)
Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
The origin and infinitely many other points of the form (x, ax) where x is any real number.
The equation for the given points is y = x+4 in slope intercept form
Slope-intercept form
y = -0.3x-1.5 in slope intercept form
y=-3x-2
Slope=8 point=(-7,3)
y = 2x + 1.
Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
Points: (4, 8) and (2, -2)Slope: 5Equation: y = 5x-12
Points: (4, 5) and (-3, -1) Slope: 6/7 Equation: 7y = 6x+11
Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11