To find the slope of a line that is parallel to the line given by the equation ( y = 3x + 5 ), we first identify the slope of the original line. The equation is in slope-intercept form ( y = mx + b ), where ( m ) represents the slope. In this case, the slope ( m ) is 3. Lines that are parallel have the same slope, so the slope of a line parallel to this one is also 3.
A linear equation in the form y = mx + c has slope m Any line parallel to 3x + 9y = 5 has the same slope 3x + 9y = 5 → 9y = -3x + 5 → y = (-3/9)x + 5/9 → y = -⅓x + 5/9 → Every line parallel to 3x + 9y = 5 has slope -⅓.
The equation of the line given is in the form (y = 3x + 5), where the slope is the coefficient of (x). The slope of this line is 3. Since parallel lines have the same slope, the slope of any line parallel to this one would also be 3.
To find the equation of a line parallel to ( y = 3x + 5 ), we need to use the same slope, which is 3. Using the point-slope form, we can write the equation as ( y - 3 = 3(x + 2) ). Simplifying this gives ( y = 3x + 9 ). Thus, the equation of the line in slope-intercept form is ( y = 3x + 9 ).
The first line can be rewritten as y = -3x + 2. Slope = -3. Parallel lines have the same slope. y = mx + b --> m = -3, b = -5 --> y = -3x - 5
If you mean: 3x+2y = 5 then y = -3/2x+5/2 or y = -1.5x+2.5 Parallel equation: y = -1.5x+4
A linear equation in the form y = mx + c has slope m Any line parallel to 3x + 9y = 5 has the same slope 3x + 9y = 5 → 9y = -3x + 5 → y = (-3/9)x + 5/9 → y = -⅓x + 5/9 → Every line parallel to 3x + 9y = 5 has slope -⅓.
The equation of the line given is in the form (y = 3x + 5), where the slope is the coefficient of (x). The slope of this line is 3. Since parallel lines have the same slope, the slope of any line parallel to this one would also be 3.
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
-3/5 or -0.6
To find the equation of a line parallel to ( y = 3x + 5 ), we need to use the same slope, which is 3. Using the point-slope form, we can write the equation as ( y - 3 = 3(x + 2) ). Simplifying this gives ( y = 3x + 9 ). Thus, the equation of the line in slope-intercept form is ( y = 3x + 9 ).
Known equation: 3x+5y = 6 or y = -3/5x +6/5 Slope of equation: -3/5 Slope of parallel equation: -3/5 Parallel equation: y-1 = -3/5(x-3) => 5y = -3x+14 Parallel equation in its general form: 3x+5y-14 = 0
The first line can be rewritten as y = -3x + 2. Slope = -3. Parallel lines have the same slope. y = mx + b --> m = -3, b = -5 --> y = -3x - 5
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
If you mean: 3x+2y = 5 then y = -3/2x+5/2 or y = -1.5x+2.5 Parallel equation: y = -1.5x+4
Do you mean: y = -3x+5 then if so the slope is -3 and the y intercept is 5
A linear equation in the form y = mx + c has slope m The slope m' of a line perpendicular to a line with slope m is such that m'm = -1 → m' = -1/m 3x + 9y = 5 → 9y = -3x + 5 → y = (-3/9)x + 5/9 → y = -⅓x + 5/9 → its slope is -⅓ → perpendicular lines have slope m' = -1/(-⅓) = 3 → Every line perpendicular to 3x + 9y = 5 has slope 3.
y = 3x+5 is parallel to y = 3x+7