The product of the slopes of two perpendicular lines is -1. Therefore, you must do the following:
1) Calculate the slope of the original line. If you put a line into the form y = ax + b, the so-called "slope-intercept form", then "a" (i.e., whatever number is in front of the "x") is the slope. Call this slope "m".
2) To get the slope of the perpendicular line, divide -1 by m. For example, if a certain line has a slope of 2, then the perpendicular line has a slope -1/2.
If you mean y = -13x then the slope of the line perpendicular to it is 1/13
Slope of a line perpendicular to x-y=16
9 is.
If you mean: y = 4x+5 then the perpendicular slope is -1/4
If you mean: y = -2x+17 then the perpendicular slope line is 1/2 or 0.5
5
If you mean y = -13x then the slope of the line perpendicular to it is 1/13
Slope of a line perpendicular to x-y=16
9 is.
A line perpendicular to the y-axis is a horizontal line (slope = 0) and is of the form y = b Therefore the required line is y = 5
Slope: -9
If you mean: y = 5x-2 then the perpendicular slope is -1/5
If you mean: y = 4x+5 then the perpendicular slope is -1/4
If you mean: y = -2x+17 then the perpendicular slope line is 1/2 or 0.5
Write the given equation in the slope-intercept form, y = mx + b, where m is the slope of the line.9x - 3y = -81 (subtract 9x to both sides)-3y = -9x - 81 (divide by -3 to both sides)y = 3x + 27Thus, the slope of the line is 3.
9
A perpendicular line has the negative reciprocal of the slope. The perpendicular line has a slope of 1/2 y=1/2 + 3 The 3 or y-intercept can really be any number though.