X=5 is a vertical line, so it has no slope. When I say it has no slope, I don't mean the slope is 0, I mean the slope is nonexistent.
If you mean x-y = 5 then y = x-5 whereas it has a slope of 1 and a y intercept of -5
If: x+y = 5 Then: y = -x+5 which is now in slope-intercept form
x + 5y = 3x - x + 5y = -x + 35y = -x + 3(5y)/5 = (-x + 3)/5y = -(1/5)x + 3/5 The slope-intercept form, y = mx + b, where (slope) m = - 1/5 and (y-intercept) b is 3/5.
The slope is -1.25
X=5 is a vertical line, so it has no slope. When I say it has no slope, I don't mean the slope is 0, I mean the slope is nonexistent.
If you mean x-y = 5 then y = x-5 whereas it has a slope of 1 and a y intercept of -5
Undefined slope.
x-4y = 5 -4y = -x+5 y = 0.25x-1.25 which is now in slope intercept form
The equation y=x-5, has a slope of "one". An equation in the form of y=mx+b has a slope of "m" and the y-intercept of "b".
If: x+y = 5 Then: y = -x+5 which is now in slope-intercept form
x + 5y = 3x - x + 5y = -x + 35y = -x + 3(5y)/5 = (-x + 3)/5y = -(1/5)x + 3/5 The slope-intercept form, y = mx + b, where (slope) m = - 1/5 and (y-intercept) b is 3/5.
The slope is -1.25
slope = -1y-intercept = 5
After solving for y you will get y=1/5 x+1. The slope of this line is 1/5.
-27
7x is still the slope, no matter what x equals.