Q: What is the smallest odd integer with exactly 6 factors?

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The smallest is 121.

3, which can be divided by the odd numbers 1 and 3.

Every integer is either even (divisible by 2) or odd (not divisible by 2). Since an even number plus 1 is odd and an odd number plus one is even, because 1 does not divide 2. We know (n + 4) is odd. The next integer is (n + 4 + 1) = (n + 5), because an odd number plus 1 is even, (n + 5) is even. The integer after (n + 5) is (n + 6), since (n + 5) we know is even, (n + 6) must be odd. Since (n + 6) is the smallest integer that is greater than (n + 4) and is odd, so (n + 6) is the next odd integer.

Any positive integer with more than two factors is composite.

If x is the smallest odd integer, then x = 2n + 1 for some integer n. Then the next two odd integers are 2n + 3 and 2n + 5 So the question then becomes: 2n+1 + (2n+3) + (2n+5) = 45 or 6n + 9 = 45 to be solved for n and thence the smallest of the three consecutive odd integers.

Related questions

105. Its factors are 1, 3, 5, 7, 15, 21, 35, and 105.

A composite number is a number with more than 2 positive integer factors. The smallest such odd number is 9.

How about: 1201 as the smallest odd integer larger than 1200

The smallest four digit odd integer is 1001.

The smallest is 121.

-10001

59,61,63,65 It is 59

It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.

It is 91125.

I don't know if it's the smallest, but 94,143,178,827 has 24 factors.

3, which can be divided by the odd numbers 1 and 3.

231 / 3 = 77So 76 + 77 +78 = 23177