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First Equation ~ 3x-y=0 Second Equation ~ 5y=15

Divide by five on both sides on the second equation to get y=3

Substitute y=3 into the first equation to get 3x-(3)=0

Add the three to both sides to cancel the three on the left to get 3x=3

Divide both sides by 3 to get x=1

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Q: What is the solution for 3x-y equals 0 and 5y equals 15?
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