First Equation ~ 3x-y=0 Second Equation ~ 5y=15
Divide by five on both sides on the second equation to get y=3
Substitute y=3 into the first equation to get 3x-(3)=0
Add the three to both sides to cancel the three on the left to get 3x=3
Divide both sides by 3 to get x=1
x = 0 and y = 4
(-5, 2)
5y + x = 0 subtract 5y from each side, then x = -5y
18y+5y+48+15 = 270 18y+5y = 270-48-15 23y = 207 y = 9
If y equals 3, 7 - 5y would be:7 - 5(3)Simplify.7 - 15 = -8.In conclusion, 7 - 5y = -8.
This is Simultaneous equ'ns. 3x + 5y = -1 2x -5y = 16 Add the two eq'ns. This will eliminate 'y' Hence 5x = 15 x = 3 When x = 3 , substitute into either eq'n to yimnd 'y'. Hence 3)3) + 5y = -1 9 + 5y = -1 5y = -10 y = -10/5 = -2 So the solution in ( x,y) form is ( 3, -2).
That equals 2xy + 3y which factors to y(2x + 3)
5y + 7 = 25y = -5y = -1
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
x = 0 and y = 4
(-5, 2)
3X = 15 + 5y does not have a single answer. The answer forms a line on the Cartesian plane. In order to reach a single solution you must have two equations when there are two unknowns.
15
5y + x = 0 subtract 5y from each side, then x = -5y
No solution
18y+5y+48+15 = 270 18y+5y = 270-48-15 23y = 207 y = 9
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