-5
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
Yes
x = 19
The 'solution' of an equation is the number which, when substitutedfor the variable, makes the equation a true statement.You have said: [ x = 5 ] .We claim that the solution is '5', because when '5' is substituted for 'x',the equation reads5 = 5and that's a true statement.
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
-5
6
It is a linear equation in x. The equation has the solution x = 0.
14x = 5 x = 5/14
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
The solution to the equation is x = 26/5 = 5.2
Yes
x = 19
4y + 2 = 5y - 5
The 'solution' of an equation is the number which, when substitutedfor the variable, makes the equation a true statement.You have said: [ x = 5 ] .We claim that the solution is '5', because when '5' is substituted for 'x',the equation reads5 = 5and that's a true statement.