ax2 + bx +c is an expression, not an equation. It cannot, therefore, have a solution. If the question concerns the equation ax2 + bx + c = 0 then the answer is ax2 - 16ax + 64a = 0 for any a other than 0.
ax3 + bx2 + cx x(ax2 + bx + c) you get one answer as 0.
y = ax2 + bx + c
If you mean: ax2+bx+c = 0 then this is the formula for a quadratic equation whereas a is greater than zero
ax2 + bx + c = 0
ax2 + bx +c is an expression, not an equation. It cannot, therefore, have a solution. If the question concerns the equation ax2 + bx + c = 0 then the answer is ax2 - 16ax + 64a = 0 for any a other than 0.
a = bx + c bx + (c-a) = 0 x = (a-c)/b It's simple because there is only one solution. This is a quadratic equation: ax2 + bx + c = 0 It has two solutions.
If you mean: ax2+bx+c = 0 then it's the general form of a quadratic equation
ax3 + bx2 + cx x(ax2 + bx + c) you get one answer as 0.
Two: one is 0, the other is -b/a ax2 + bx + c = 0, but c = 0 ⇒ ax2 + bx + 0 = 0 ⇒ ax2 + bx = 0 ⇒ x(ax + b) = 0 ⇒ x = 0 or (ax + b) = 0 ⇒ x = -b/a
y = ax2 + bx + c
Why are Quadratic equations, which are expressed in the form of ax2 + bx + c = 0, where a does not equal 0,
If you mean: ax2+bx+c = 0 then this is the formula for a quadratic equation whereas a is greater than zero
ax2 + bx + c = 0
ax2 +bx + c = 0
If you mean: ax2+bx+c = 0 which is the general form of a quadratic equation whereas a is > 0 and any increases to the value of a will effect the solutions of the equation.
ax^2+bx+c=0 is the standard form of a quadratic function.