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Some of the operands are missing (due to limitation of editor?) and hence assuming the equation is x^2+5x-5 = 0. The roots are

(-5 + sqrt(25+20))/2 and (-5 - sqrt(25+20))/2

(-5 + sqrt(45))/2 and (-5 - sqrt(45))/2

(-5 + 6.70)/2 and (-5 - 6.70)/2

(1.70)/2 and (-11.70)/2

0.85 and -5.85

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12y ago
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Q: What is the solution set of x2 5x - 5 0?
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