(a - 2b)(2a - b)
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
There are no like terms here.
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
It is: 2b squared
(a + 2b)(a + 2b)
2b - 1
5b + 11 - 2b = 3b + 11
20a plus 14 will be 34a minus 8a minus 7 34a minus 8 is 26a minus 7 is 19a. The single b is 1b plus 6b which is 7b minus 2b equals 5b.
3a - 2b
-2bk2 + 6bk - 2b = -2b(k2 - 3k + 1)
It is an algabraic expession without knowing whether or not 2b and 3a are plus or minus
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals". There is no visible symbol between " ... equals 4" and "2b plus 1".
(a + 2b)(c + 2d)
That will depend on the plus or minus value of 10 or maybe there is a missing equality sign.
4(a + 2b - 4c)
The Answer to this question is 9 (2B+4) and (1B+3)
b2 x 2b = 2b3
(a - 2b)(c - 3d)