x2 - 6x = 16 ∴ x2 - 6x + 9 = 25 ∴ (x - 3)2 = 25 ∴ x - 3 = 25 ∴ x = 28
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
x = - 4 - or + the square root of 3 Solved by using the quadratic equation formula.
Without an equality sign the given expression is not an equation but if you mean -6x = 321 then the value of x works out as -53.5 which is the solution to the equation.
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
it is not an equation (there no equality in it!)
x2 + 10x + 25 --> (x + 5)2
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
x2 - 6x = 16 ∴ x2 - 6x + 9 = 25 ∴ (x - 3)2 = 25 ∴ x - 3 = 25 ∴ x = 28
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
If x2 < 25 Then: |x| < 5 -5 < x < 5
x = - 4 - or + the square root of 3 Solved by using the quadratic equation formula.
x^2<25
salt with water is a soultion
Without an equality sign the given expression is not an equation but if you mean -6x = 321 then the value of x works out as -53.5 which is the solution to the equation.
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
2x2=4 x2=8 x2=16 x2 = 32 and 5x5 = 25 so no, I guess not.