Assuming the sides are also given in feet, we can use Heron's formula to get the area:
A = √(p(p-a)(p-b)(p-c)),
where p is half the perimeter, or p = (a+b+c)/2
So, calculating p:
p = (7 + 24 + 25) / 2 = 56 / 2 = 28
Then, for the area:
A = √(28 x (28-7) x (28-24) x (28-25))
= √(28 x 21 x 4 x 3)
= √7056
A = 84 ft²
It is a right angle triangle with an hypotenuse of 39 and sides of 36 and 15. Area of triangle is 0.5*36*15 = 270 square units
Area = 0.5*5*12 = 30 square units
First find the area of the square (length x width) then find the area of the triangle (base x height x 2) and add the two answers together.Quadrilateral just means "four sides", but the sides have to be straight.Assuming it's a right-angle triangle? Such a triangle is half of a rectangle or square, so times by 2).
The area of triangle is : 75.0
12.5m2
It is a right angle triangle with an hypotenuse of 39 and sides of 36 and 15. Area of triangle is 0.5*36*15 = 270 square units
Area = 0.5*5*12 = 30 square units
First find the area of the square (length x width) then find the area of the triangle (base x height x 2) and add the two answers together.Quadrilateral just means "four sides", but the sides have to be straight.Assuming it's a right-angle triangle? Such a triangle is half of a rectangle or square, so times by 2).
The two equal sides each measure 8 inches
The area of triangle is : 75.0
They relate by helping you find the area of each square, what relationships excises among them
It is: 0.5*25*20 = 250 square inches It doesn't matter whether or not a triangle is a right triangle; the area is always half of the base times the height.
12.5m2
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
Area = 30.549 square units.
Area of the right isosceles triangle: 0.5*16*16 = 128 square units
A right triangle is easy, simply multiply the two sides and divide by two