It is 50*51/2 = 1275.
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The sum of the numbers 1 through 50 can be found using the formula for the sum of an arithmetic series: [(n/2) * (first term + last term)], where n is the number of terms. In this case, n = 50 and the first term is 1 and the last term is 50. Plugging those values into the formula, the sum is 1275.
51
(n)( n+1)/2 where n = 50. (50 x 51)/2 = 2,525
1/2, or 50%.1/2, or 50%.1/2, or 50%.1/2, or 50%.
rearrange 1 to 50 so that you see this pattern: 50 = 50 1+49 = 50 2+48 = 50 ... 24+26 = 50 25 = 25 then add this up: 25 x 50 + 25 = 1275
It is instructive to note that you can rewrite 1+2+3+4....+99+100 as 1+100+2+99+3+98....+50+51 Then you can group each pair of numbers as (1+100)+(2+99)+(3+98)+...+(50+51) All of these couplets add up to 101, and there are 50 of them. Thus the sum of the first 100 whole numbers is 50x101. This can be calculated at 5,050.