Finding the sum of numbers means adding them. So: 6 + 1 =7 The sum of six and one is seven.
Using 1-6 can a magic triangle have a sum of 13
The probabilityof ROLLING a sum of 12 is 1/36 ( 1 in 6 for each die = 1/6 x 1/6 = 1/36) The probabilityof NOT ROLLING a sum of 12 is 35/36 ( 1 - 1/36)
the sum of six and one becuase that equals 7 and the product of six and one equals 6
1
Do this in reverse. The sum of -1 and -1 is -1+-1=-2 The difference of -6 and -6 is -6-(-6)=-6+6=0 0 increased by -2 is 0+-2=-2 The sum of 10 and -2 is 10+-2=8 Translation: 8
1
It is: 5+1 = 6
Finding the sum of numbers means adding them. So: 6 + 1 =7 The sum of six and one is seven.
200 + {(5 + 6) / 1} = 211
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
Using 1-6 can a magic triangle have a sum of 13
The probabilityof ROLLING a sum of 12 is 1/36 ( 1 in 6 for each die = 1/6 x 1/6 = 1/36) The probabilityof NOT ROLLING a sum of 12 is 35/36 ( 1 - 1/36)
the sum of six and one becuase that equals 7 and the product of six and one equals 6
1/6 + 1/6 = 2/6 = 1/3
6 and -1
-1