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Rusty Hahn
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What is the sum of something?
What you get when you add two things together. 1 + 1 = 2. The sum of 1 and 1 is 2.
When Rolling 2 dice which outcome is more likely a sum of 2 or a sum of 4?
A sum of 4 is more likely. Out of the 36 possible outcomes with a pair of 6-sided dice, only one will have a sum of 2 {1-1}. Three of the possibilities sum to 4. {1-3, 2-2, 3-1}
What is the sum of the first 5 numbers squared?
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
CAn the sum of two mixed numbers be two?
Only if you include negatives. The sum of 3 and 1/2 + -1 and 1/2 equals 2.
Can the sum of two mixed number be equal to 2 explain why or why not?
Only if you include negatives. The sum of 3 and 1/2 + -1 and 1/2 equals 2.
What is the sum of 1 and 1?
The sum of 1 and 1 is 2.
How do you get the sum of something?
Sum is the term for the answer to addition. Any time you add something, you get the sum. 1 + 1 = 2 2 is the sum.
What is the sum of all the positive proper fractions with denominators less than or equal to 100?
Consider a denominator of r; It has proper fractions: 1/r, 2/r, ...., (r-1)/r Their sum is: (1 + 2 + ... + (r-1))/r The numerator of this sum is 1 + 2 + ... + (r-1) Which is an Arithmetic Progression (AP) with r-1 terms, and sum: sum = number_of_term(first + last)/2 = (r-1)(1 + r-1)/2 = (r-1)r/2 So the sum of the proper fractions with a denominator or r is: sum{r} = ((r-1)r/2)/r = ((r-1)r/2r = (r-1)/2 Now consider the sum of the proper fractions with a denominator r+1: sum{r+1} = (((r+1)-1)/2 = ((r-1)+1)/2 = (r-1)/2 + 1/2 = sum{r) + 1/2 So the sums of the proper fractions of the denominators forms an AP with a common difference of 1/2 The first denominator possible is r = 2 with sum (2-1)/2 = ½; The last denominator required is r = 100 with sum (100-1)/2 = 99/2 = 49½; And there are 100 - 2 + 1 = 99 terms to sum So the required sum is: sum = ½ + 1 + 1½ + ... + 49½ = 99(½ + 49½)/2 = 99 × 50/2 = 2475
What is the sum of the digits of the number 11?
1 + 1 = 2 The sum of the digits is therefore 2.
What is the sum of 1 2 1?
1 + 2 + 1 = 4
Can the sum of two mixed numbers equal 2?
Only if you include negatives. The sum of 3 and 1/2 + -1 and 1/2 equals 2.
Can someone translate this the sum of a number and ten is the difference of -6 and -6 increased by the sum of -1 and -1?
Do this in reverse. The sum of -1 and -1 is -1+-1=-2 The difference of -6 and -6 is -6-(-6)=-6+6=0 0 increased by -2 is 0+-2=-2 The sum of 10 and -2 is 10+-2=8 Translation: 8
What is an equation to find the sum of all the integers from 1 to 2010?
To calculate the sum of the numbers 1 to n, the formula is: sum = n(1 + n) / 2 So, an equation to find the sum of the integers 1 to 2010 is: sum = 2010 x (1 + 2010) / 2
What is the sum of the first 1400 consecutive odd numbers?
The sum of the first 1400 odd numbers is 1960000. The sum of an arithmetic progression is given by: sum = n/2 (2a + (n-1)d) where n is the number of items (in this case n = 1400) where a is the first number (in this case a = 1) where d is the common difference between terms (in this case d = 2) Thus: sum = 1400/2 × (2×1 + (1400 - 1)×2) → sum = 1400/2 × 2(1 + 1400 - 1) → sum = 1400 × 1400 = 1960000
What is the sum of the first 500 consecutive odd numbers?
1,000,000 * * * * * The 1st and 500th sum to (2*1-1)+(2*500-1) = 2*501 - 2 = 1000 The 2nd and 499th sum to (2*2-1)+(2*499-1) = 2*501 - 2 = 1000 There are 250 such sums So sum of all 500 odd numbers = 250*1000 = 250,000
What is the sum to 1 plus 1?
2
What is the sum of 1 plus 1?
2
