y + 3
In mathematics, "y plus 3" is an algebraic expression representing the sum of a variable 'y' and the constant 3. This expression cannot be simplified further unless the value of 'y' is known. If 'y' is a known value, then the sum can be calculated by adding 3 to that value. If 'y' is unknown, then the expression "y + 3" remains as is, representing a sum of 'y' and 3.
It is (x + y)^3 - sqrt(5x + 3y) and there is no sensible simplification of this expression.
The algebraic expression that represents fifteen less than the sum of ( y^3 ) and seven is ( (y^3 + 7) - 15 ). This simplifies to ( y^3 - 8 ).
The word sum is the clue. It means the problem will be an addition problem.y + 3(8) = ?y + 24 = ?
To find two times the sum of ( x^2 ) and ( y^2 ) increased by three times the sum of ( x^2 ) and ( y^2 ), we first express it mathematically. The sum of ( x^2 ) and ( y^2 ) is ( x^2 + y^2 ). Thus, two times this sum is ( 2(x^2 + y^2) ), and three times it is ( 3(x^2 + y^2) ). Adding these together gives ( 2(x^2 + y^2) + 3(x^2 + y^2) = 5(x^2 + y^2) ).
In mathematics, "y plus 3" is an algebraic expression representing the sum of a variable 'y' and the constant 3. This expression cannot be simplified further unless the value of 'y' is known. If 'y' is a known value, then the sum can be calculated by adding 3 to that value. If 'y' is unknown, then the expression "y + 3" remains as is, representing a sum of 'y' and 3.
3(y+7)
(x+y)+3
y, y+2, y+4
It is (x + y)^3 - sqrt(5x + 3y) and there is no sensible simplification of this expression.
5
The algebraic expression that represents fifteen less than the sum of ( y^3 ) and seven is ( (y^3 + 7) - 15 ). This simplifies to ( y^3 - 8 ).
The word sum is the clue. It means the problem will be an addition problem.y + 3(8) = ?y + 24 = ?
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
3x over x + y
To find two times the sum of ( x^2 ) and ( y^2 ) increased by three times the sum of ( x^2 ) and ( y^2 ), we first express it mathematically. The sum of ( x^2 ) and ( y^2 ) is ( x^2 + y^2 ). Thus, two times this sum is ( 2(x^2 + y^2) ), and three times it is ( 3(x^2 + y^2) ). Adding these together gives ( 2(x^2 + y^2) + 3(x^2 + y^2) = 5(x^2 + y^2) ).