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8 + y
8+y is the sum of 8 and y
abs(y^3 - 4) < 8*y
Sum of digits x+y=8 Two digit no assume as 10x+y It is given that 10x+y+18=10y+x 9x-9y+18=0 x-y=-18/9 x-y= -2 Equate both x+y-8=x-y+2 2y=10 y= 5 Substitute this y in x+y x+5=8 x=3 So 35 is original two digit no Reversed new no is 53
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3