The sum of 5/6 and 5/6 is 1 2/3
6
The subject of this question is "sum". 5x6 - (5+6) is 19
There are 216 permutations of three standard dice. Of these, there are exactly 10 that sum to 15, namely 3-3-6, 4-5-6, 4-6-5, 5-4-6, 5-5-5, 5-6-4, 6-3-6, 6-4-5, 6-5-4, and 6-6-3. The probability, then, of rolling a sum of 15 with three standard dice is 10 in 216, or 5 in 108, or about 0.04630.
-1 (:
product means multiplication sum means adding. 6 * 5 = 30 6 + 5 = 11
The sum of 5/6 and 5/6 is 1 2/3
5x + 6
6 + 5 = 11
0.8333
It is: 5+1 = 6
-1
6
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
200 + {(5 + 6) / 1} = 211
The subject of this question is "sum". 5x6 - (5+6) is 19
Assuming it is an addition sum - in any addition sum such as 5 + 6 = 11, the numbers 5 and 6 are called addends.