The sum of the odd numbers (from 1) up to to 500 is 62500. The sum of an arithmetic series is given by: sum = 1/2 x number_in_series x (first + last) For the odd numbers from 1 to 500, there is: number_in_series = 250 first = 1 last = 499 which gives the sum as: sum = 1/2 x 250 x (1 + 499) = 62500.
The sum of the first n odd numbers is n squared. 25 x 25 = 625
x+x+2 The x is the first integer and x+2 is the odd integer since odd numbers are every other number. so the sum therefore is x+x+2
This is very easy. Simply square the number: 100 squared (100 x 100) = 10,000. So, the sum of the first 100 odd numbers is 10,000.
Let's call the first odd number x. Since the numbers are consecutive, the second odd number would be x + 2. The sum of the two numbers is 44, so the equation would be x + (x + 2) = 44. Solving this equation yields x = 21, which means the two consecutive odd numbers are 21 and 23.
The sum of the odd numbers (from 1) up to to 500 is 62500. The sum of an arithmetic series is given by: sum = 1/2 x number_in_series x (first + last) For the odd numbers from 1 to 500, there is: number_in_series = 250 first = 1 last = 499 which gives the sum as: sum = 1/2 x 250 x (1 + 499) = 62500.
640000. First odd number is 1, 800th odd number is 1599, giving their sum: sum = number_of_numbers x (first_number + last_number) ÷ 2 = 800 x (1 + 1599) ÷ 2 = 640000
The sum of the first n odd numbers is n squared. 25 x 25 = 625
x+x+2 The x is the first integer and x+2 is the odd integer since odd numbers are every other number. so the sum therefore is x+x+2
This is very easy. Simply square the number: 100 squared (100 x 100) = 10,000. So, the sum of the first 100 odd numbers is 10,000.
You square the number of integers you are looking for, in this case; 300. So, 300 squared = 300 x 300 = 90,000. Thus, the sum of the first 300 odd numbers is 90,000.
The first odd number is 1 The 1000th odd number is 1000 x 2 - 1 = 1999 Sum = number_of_numbers x (first_number + last_number) ÷ 2 = 1000 x (1 + 1999) ÷ 2 = 1000 x 2000 ÷ 2 = 1000000
The sum_of_a_series = 1/2 x number_in_series x (first_number + last_number) The first odd number is 2 x 1 - 1 = 1, the 55th odd number is 2 x 55 - 1 = 109 Sum = 1/2 x 55 x (1 + 109) = 1/2 x 55 x 110 = 552 = 3025 It can be seen that the sum of the first n consecutive odd numbers is always n2: sum = n/2(1 + (2n - 1)) = n/2(2n) = n2
You can work this out by realizing that the sum of the first x odd numbers is equal to x2.Consider the following examples:The first three odd numbers: 1 + 3 + 5 = 9The first five odd numbers: 1 + 3 + 5 + 7 + 9 = 25The first ten odd numbers: 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 = 100In each case, the number of odds you're adding together is the square root of their sum. This means that the first 1500 consecutive odd numbers have a sum of 15002, which equals 2250000, or two and a quarter million.
Let's call the first odd number x. Since the numbers are consecutive, the second odd number would be x + 2. The sum of the two numbers is 44, so the equation would be x + (x + 2) = 44. Solving this equation yields x = 21, which means the two consecutive odd numbers are 21 and 23.
The sum of the first 5,000 odd numbers is 25,000,000 (25 million). This is an easy calculation. Simply square the number of integers you are looking to calculate. In this case 5,000 squared = 5,000 x 5,000 = 25 million.
call the first number x. The second number would be x + 2 (as they're consecutive odd numbers). The sum of both numbers would be x + x + 2 = 28, or 2x + 2 = 28. This can be evaluated to 2x = 26, x = 13. The first number would be 13, the second 15, 13 + 15 = 28.