0
What else can I help you with?
When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
When x3 plus 3x2-2x plus 7 is divided by x plus 1 the remainder is?
== == Suppose f(x) = x3 + 3x2 - 2x + 7 divisor is x + 1 = x - (-1); so rem = f(-1) = 11
How do you factor 7x cubed plus 2x?
7 x3 + 2 x = x (7 x2 + 2)
How do you write sum of twice a number plus seven?
2x+7=n
4x2 plus 28x plus 49?
4x2 + 28x + 49 = 4x2 + 14x + 14x + 49 = 2x(2x + 7) + 7(2x + 7) = (2x + 7)(2x + 7) or (2x + 7)2
When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
When x3 plus 3x2 2x plus 7 is divided by x plus 1 the remainder is?
That depends on whether or not 2x is a plus or a minus
When x3 plus 3x2-2x plus 7 is divided by x plus 1 the remainder is?
== == Suppose f(x) = x3 + 3x2 - 2x + 7 divisor is x + 1 = x - (-1); so rem = f(-1) = 11
How do you factor 7x cubed plus 2x?
7 x3 + 2 x = x (7 x2 + 2)
How do you write sum of twice a number plus seven?
2x+7=n
2x3 - 7 plus 5x2 - x3 plus 3x - x3?
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
X plus 2y equals 8 2x plus y equals 7?
Sum Numb!
What is the factorization of x3 plus 2x2-35x?
x3 + 2x2 - 35x = x(x2 + 2x - 35) = x(x + 7)(x - 5)
4x2 plus 28x plus 49?
4x2 + 28x + 49 = 4x2 + 14x + 14x + 49 = 2x(2x + 7) + 7(2x + 7) = (2x + 7)(2x + 7) or (2x + 7)2
What is 2x plus 8y plus 7 equals 0?
2x = -7 - 8y
The sum of twice a number 7?
2x + 7
What is the sum of (x-4) plus (2x-7)?
(x - 4) + (2x - 7) = 3x - 11 You get that by: Adding the x terms (one plus two) to get 3x; and adding the plain (non-x) numbers together. In this can both plain numbers are negative, so you get a negative of eleven, which is the sum of the absolute values 4 and 7.
