x-7
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
This depends on what "x" is. The sum of the first x odd numbers is equal to x^2 or x*x.
x=5
x+y
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
x-7
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
the sum equals x+10
the cube of the sum x and 4
Le the "number" be x. The sum is x + 6.
public int sum(int[] x) {int sum = 0;for(int i : x) {sum += i;}return sum;}public int average(int[] x) {// Note that this returns an int, truncating any decimalreturn sum(x) / x.length;}
This depends on what "x" is. The sum of the first x odd numbers is equal to x^2 or x*x.
x+15 if you are trying to find the value of x it would be x+15 x=-15
The sum of x and y decreased by their product is (x + y)- xy.
No. The sum of (x) and (x+6) is (2x + 6), not 6. What you want is (x) and (6 - x). The sum of those two is always 6, no matter what 'x' is.
x + 8