x-7
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
This depends on what "x" is. The sum of the first x odd numbers is equal to x^2 or x*x.
The sum of 16 and x can be represented as 16 + x. This is an algebraic expression that combines the value of 16 with an unknown variable x. In order to find the sum, you would need to know the specific value of x. Without knowing the value of x, the sum remains as 16 + x.
x=5
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
x-7
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
the sum equals x+10
Le the "number" be x. The sum is x + 6.
public int sum(int[] x) {int sum = 0;for(int i : x) {sum += i;}return sum;}public int average(int[] x) {// Note that this returns an int, truncating any decimalreturn sum(x) / x.length;}
This depends on what "x" is. The sum of the first x odd numbers is equal to x^2 or x*x.
x+15 if you are trying to find the value of x it would be x+15 x=-15
The sum of x and y decreased by their product is (x + y)- xy.
No. The sum of (x) and (x+6) is (2x + 6), not 6. What you want is (x) and (6 - x). The sum of those two is always 6, no matter what 'x' is.
x + 8
x=5