Ccv + x + x = 225
The brilliant and witty Wikianswers auto-corrector will not allow me to capitalize the above Roman numerals, per standard usage. Sorry.
x-7
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
To find the sum of x and y, you simply add the two variables together: sum = x + y. If you have specific values for x and y, you can substitute them into this equation to calculate the sum. Otherwise, the sum remains expressed as x + y.
To calculate the slope of the trend line, I used the formula ( m = \frac{(N \sum xy) - (\sum x)(\sum y)}{(N \sum x^2) - (\sum x)^2} ), where ( N ) is the number of data points, ( \sum xy ) is the sum of the product of each pair of x and y values, ( \sum x ) is the sum of the x values, ( \sum y ) is the sum of the y values, and ( \sum x^2 ) is the sum of the squares of the x values. This formula derives from the least squares method, which minimizes the distance between the actual data points and the trend line. After computing the necessary sums, I substituted them into the formula to find the slope.
This depends on what "x" is. The sum of the first x odd numbers is equal to x^2 or x*x.
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
x-7
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
the sum equals x+10
To find the sum of x and y, you simply add the two variables together: sum = x + y. If you have specific values for x and y, you can substitute them into this equation to calculate the sum. Otherwise, the sum remains expressed as x + y.
Le the "number" be x. The sum is x + 6.
public int sum(int[] x) {int sum = 0;for(int i : x) {sum += i;}return sum;}public int average(int[] x) {// Note that this returns an int, truncating any decimalreturn sum(x) / x.length;}
This depends on what "x" is. The sum of the first x odd numbers is equal to x^2 or x*x.
The sum of 16 and x can be represented as 16 + x. This is an algebraic expression that combines the value of 16 with an unknown variable x. In order to find the sum, you would need to know the specific value of x. Without knowing the value of x, the sum remains as 16 + x.
x+15 if you are trying to find the value of x it would be x+15 x=-15
The sum of x and y decreased by their product is (x + y)- xy.
No. The sum of (x) and (x+6) is (2x + 6), not 6. What you want is (x) and (6 - x). The sum of those two is always 6, no matter what 'x' is.