The question cannot be answered because the information is not provided in a sensible form. What does a "base of 16" mean? A base which is a 16 sided polygon? A base, each of whose sides (however many) are 16 units long? A base of some indeterminate shape whose area is 16 square units? Something else?
In order for us to answer a question sensibly, such information is required. We should not be expected to read your mind, make guesses, or give a set of answers which will cover all possible interpretations!
Surface Area= 1/2perimeter x slant height + B * * * * * Perimeter = perimeter of base. B = Area of base.
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
False
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
It is impossible to answer the question without knowing the shape of the base, which will determine how many sloped triangles there are.
Surface Area= 1/2perimeter x slant height + B * * * * * Perimeter = perimeter of base. B = Area of base.
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
It is not possible to answer the question because the shape of the base is not known. As a result the surface area of the base, and hence the total surface area cannot be calculated.
False
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
It is impossible to answer the question without knowing the shape of the base, which will determine how many sloped triangles there are.
It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.
Surface area of any pyramid is 1/2Pl + B; where P=perimeter of the base, l=slant height and B= Area of the base.
Find the surface area of each individual face and then add them together to give the total surface area of the pyramid.
120
The surface area of a cone: SA = pi*r² + pi*r*s (r is radius, s is slant height) The surface area of a pyramid: SA = [1/2 * Perimeter * Slant Height] + [Base Area]
It is the lateral area (which is 1/2 the perimeter multiplied by the slant height), plus the area of the base.