Algebraically, with X = integers.
X + (X + 1) + (X + 2) = 192
3X + 3 = 192
3X = 189
X = 63
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There is no set of three consecutive integers for 106.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
There are no three consecutive odd integers who's sum equals 13.
20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22
The integers are -19, -18 and -17.