Since infinity is not a defined number, it is impossible to have a square root of it. its infinity!
Infinity
17.72 + ∞
sqrt(x) Range: {0,infinity)
This question appears to have been phrased incorrectly as it appears nonsensical. 9x + 117 = 2x + 17 = 2x There is only one value for x where one could suggest this holds true and that is if x is equal to infinity. Therefore the square root of x will also equal infinity. If 2x = 2x + 17 then we have to seek a value for x where "adding to it" does not change the value. The only value could be infinity. It is a nonsense to talk of adding to infinity however. I suspect that this question has been mistyped somehow, but have answered it as written.
Since infinity is not a defined number, it is impossible to have a square root of it. its infinity!
Anawer is Infinity
The value of (\sqrt{2} \times \sqrt{2}) is equal to 2, as the square root of a number multiplied by itself cancels out the square root and leaves the number. There is no concept of multiplying by infinity in this context as infinity is not a specific number but rather a concept representing unboundedness.
Infinity
Infinity
What is the limit as x approaches infinity of the square root of x? Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.
infinity is not considered a number it is considered a theory therefore it can not be square rooted
17.72 + ∞
The answer is infinite.
0.5
The square root of 6 is an irrational number, approximately equal to 2.44948974278. When you take the square root of 6 and continue to do so to infinity, the number will not converge to a specific value but will approach the square root of 6. This means that as you take the square root of the result repeatedly, the number will get closer and closer to approximately 2.44948974278 but will never exactly reach it.
CoolFunny XDAnd...Smart! Pie = 3.14 The square root of infinity is infinity =|