The answer to this whimsical but useless exercise is: Infinity
Since infinity is not a defined number, it is impossible to have a square root of it. its infinity!
Infinity
17.72 + ∞
sqrt(x) Range: {0,infinity)
This question appears to have been phrased incorrectly as it appears nonsensical. 9x + 117 = 2x + 17 = 2x There is only one value for x where one could suggest this holds true and that is if x is equal to infinity. Therefore the square root of x will also equal infinity. If 2x = 2x + 17 then we have to seek a value for x where "adding to it" does not change the value. The only value could be infinity. It is a nonsense to talk of adding to infinity however. I suspect that this question has been mistyped somehow, but have answered it as written.
Since infinity is not a defined number, it is impossible to have a square root of it. its infinity!
Anawer is Infinity
The value of (\sqrt{2} \times \sqrt{2}) is equal to 2, as the square root of a number multiplied by itself cancels out the square root and leaves the number. There is no concept of multiplying by infinity in this context as infinity is not a specific number but rather a concept representing unboundedness.
Infinity
Infinity
What is the limit as x approaches infinity of the square root of x? Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.
infinity is not considered a number it is considered a theory therefore it can not be square rooted
17.72 + ∞
The answer is infinite.
0.5
take x = root 6+ root 6.............upto infinityx = root 6 + x ........ie take root six once and keep the n number of root 6 as xsquare on both sidesx2 = 6 + xx2 - x- 6 = 0 solve this quadratic equations.you will get x= 3 or -2but x is not -2 as it will not satisfyso x = 3thus the valueroot 6 plus root 6 till infinity = 3
CoolFunny XDAnd...Smart! Pie = 3.14 The square root of infinity is infinity =|