For the tangential value tan θ = 1/2, the angle θ is 26.565° (0.464 radians).
The tangent is the opposite side over the adjacent side for an angle,
or otherwise sin θ /cos θ.
tan 2 pi = tan 360º = 0
tan 165/2 = 1.068691
If tan A = 1/2, then sin A = ? We use the Pythagorean identity 1 + cot2 A = csc2 A to find csc A, and then the reciprocal identity sin A = 1/csc A to find sin A. tan A = 1/2 (since tan A is positive, A is in the first or the third quadrant) cot A = 1/tan A = 1/(1/2) = 2 1 + cot2 A = csc2 A 1 + (2)2 = csc2 A 5 = csc2 A √5 = csc A (when A is in the first quadrant) 1/√5 = sin A √5/5 = sin A If A is in the third quadrant, then sin A = -√5/5.
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
If B is 90 degrees, Tan A is BC / AB. But I don't know what you mean by Tan A by 2.
The value of tan A is not clear from the question.However, sin A = sqrt[tan^2 A /(tan^2 A + 1)]
1
Tan(3a_)(sqrt(2) / 2 )(sqrt(2)/2) + 0.5 Tan(3a) ( 2/4) + 1/2 Tan(3a) ( 1/2 + 1/2 ) Sin(3a) (1) / 2Cos(3a) + 1/2 Without beinf equated to anything this will not go any further.
To find the exact value of tan 105°. First, of all, we note that sin 105° = cos 15°; and cos 105° = -sin 15°. Thus, tan 105° = -cot 15° = -1 / tan 15°. Using the formula tan(α - β) = (tan α - tan β) / (1 + tan α tan β); and using, also, the familiar values tan 45° = 1, and tan 30° = ½ / (½√3) = 1/√3 = ⅓√3; we have, tan 15° = (1 - ⅓√3) / (1 + ⅓√3); whence, cot 15° = (1 + ⅓√3) / (1 - ⅓√3) = (√3 + 1) / (√3 - 1) {multiplying through by √3} = (√3 + 1)2 / (√3 + 1)(√3 - 1) = (3 + 2√3 + 1) / (3 - 1) = (4 + 2√3) / 2 = 2 + √3. Therefore, tan 105° = -cot 15° = -2 - √3, which is the result we sought. We are asked the exact value of tan 105°, which we gave above. We can test the above result to 9 decimal places, say, by means of a calculator: -2 - √3 = -3.732050808; and tan 105° = -3.732050808; thus indicating that we have probably got the right result.
tan 2 pi = tan 360º = 0
tan u/2 = sin u/1+cos u
The exact value of 60 degrees would be 1/2. This is a math problem.
3
tan 165/2 = 1.068691
If tan A = 1/2, then sin A = ? We use the Pythagorean identity 1 + cot2 A = csc2 A to find csc A, and then the reciprocal identity sin A = 1/csc A to find sin A. tan A = 1/2 (since tan A is positive, A is in the first or the third quadrant) cot A = 1/tan A = 1/(1/2) = 2 1 + cot2 A = csc2 A 1 + (2)2 = csc2 A 5 = csc2 A √5 = csc A (when A is in the first quadrant) 1/√5 = sin A √5/5 = sin A If A is in the third quadrant, then sin A = -√5/5.
Tan(45) = Sin(45) / Cos(45) Sin(45) = sqrt(2) / 2 Cos(45) = sqrt)2)/2 Hence Tan(45) = [sqrt(2) / 2] / [sqrt(2)/2] Division of fractions. [sqrt(2) / 2] / [sqrt(2)/2] => sqrt(2) /2 X 2/ sqrt(2) Cancel down by 'sqrt(2) ; 1/2 X 2/1 Cancel down by '2' 1/1 X 1/1 = 1/1 = 1 Hence Tan(45) = 1 .
If the angles are measured in degrees or gradians, then: tan 3 > tan 2 > tan 1 If the angles are measured in radians, then: tan 1 > tan 3 > tan 2.