The answer is;
54.6
But I used my TI-84 to get that answer and I can not remember how to do these.
51-2x = 0.25 51 * 5-2x = 0.25 5-2x = 0.05 -2x*ln(5) = ln(0.05) x = ln(0.05)/[-2*ln(5)] = 0.931
hanks to the limitations of the browser through which questions are posted, it is not clear what the question is but, here goes: If the question was ea = 35, then the answer is a = ln(35) where ln are the natural logarithms.
ln(a) = 5.3 a = e5.3
14\2
18
To find ln 2.33, you need a calculator. It is the solution of the equation e^x = 2.33. ln 2.33 = 0.84586 (using a calculator)
3=lnx e^3=x
In the equation ln(x) = 5, the solution is x = (about) 148.4. To solve, simply raise e to the power of both sides and reduce... ln(x) = 5 eln(x) = e5 x = 148.4
51-2x = 0.25 51 * 5-2x = 0.25 5-2x = 0.05 -2x*ln(5) = ln(0.05) x = ln(0.05)/[-2*ln(5)] = 0.931
Pi^2 times the square root of 0.3 = Ln Xi for Ln Yi it's a little tougher. (0.3^4 times the value of Ln Xi)/17.2 Hope this helped. (not)
the natural log, ln, is the inverse of the exponential. so you can take the natural log of both sides of the equation and you get... ln(e^(x))=ln(.4634) ln(e^(x))=x because ln and e are inverses so we are left with x = ln(.4634) x = -0.769165
The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)
hanks to the limitations of the browser through which questions are posted, it is not clear what the question is but, here goes: If the question was ea = 35, then the answer is a = ln(35) where ln are the natural logarithms.
e = 2.71828183 (approximately)The definition of ln is this: ln x = y when e ^ y = x. It's an inverse property... So ln x means "find out what value y would need to have so that e ^ y equals x" Since e ^ 1 = e, ln e has to equal 1. because in line equation to signify that the task/job is done. This is why it is equal to 1.cause you add them and it just does
4.60
To be logarithmic the equation would be, ( otherwise just linear ) 3x + 7 = 20 subtract 7 from each side 3x = 13 now, you know the answer is between x = 2 and x = 3, so I use natural logs both sides ln(3x) = ln(13) as this is a logarithmic operation you can bring down the x in front of the ln sign on the left x ln(3) = ln(13) divideboth sides by ln(3) x = ln(13)/ln(3) ( not ln(13/3)!!!!! ) x = 2.334717519 -------------------------check in original equation 3(2.334717519) + 7 = 20 13 + 7 = 20 20 = 20 --------------checks
Assuming your equation is: e^4x = 2981 Then taking the logs to base e (natural logs) of both sides gives: ln(e^4x) = ln(2981) → 4x = ln(2981) [Note: The 2981 looks like it has been rounded to a whole number from approx 2980.958 which means the value of x was a whole number (to which ln(2981) rounds).]