There's no way we can tell, until we know the values of 'x' and 'y'.
The values are: x = -6 and y = 10
Standard Form for a linear equation is Ax + By = C, where B is not = 0, A is >=0 and A is an integer.Sometimes ax + by + c = 0 is used instead.y = 2-3x y + 3x +2. Presto!
If y = 9x2 + 12x + 4 Then the y intercept will be when x = 0, which is 4: y = 9(0)2 + 12(0) + 4 y = 0 + 0 + 4 y = 4 The x intercept will happen when y = 0, which we can work out by finding factors of the equation and determining x values that give us a zero y value: 9x2 + 12x + 4 = 0 9x2 + 6x + 6x + 4 = 0 3x(3x + 2) + 2(3x + 2) = 0 (3x + 2)(3x + 2) = 0 (3x + 2)2 = 0 3x + 2 = 0 3x = -2 x = - 2/3 So the x intercept is at -2/3 and the y intercept is at 4.
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
(52/11, 101/11) and (-2, -11) Rearrange 3x-y = 5 into y = 3x-5 and substitute this into the curve equation and then use the quadratic equation formula to find the values of x which leads to finding the values of y by substituting the values of x into y = 3x-5.
y = 3x - 2 3x = y + 2 x = y + 2 --------- 3
There's no way we can tell, until we know the values of 'x' and 'y'.
y = 2 sin 3x y' = 2(sin 3x)'(3x)' y' = 2(cos 3x)(3) y' = 6 cos 3x
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The values are: x = -6 and y = 10
Standard Form for a linear equation is Ax + By = C, where B is not = 0, A is >=0 and A is an integer.Sometimes ax + by + c = 0 is used instead.y = 2-3x y + 3x +2. Presto!
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y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
9x^2-6xy+y^2 = (y-3x)^2 (y-3x)^2-81 -> ((y-3x)+9)((y-3x)-9)
If y = 9x2 + 12x + 4 Then the y intercept will be when x = 0, which is 4: y = 9(0)2 + 12(0) + 4 y = 0 + 0 + 4 y = 4 The x intercept will happen when y = 0, which we can work out by finding factors of the equation and determining x values that give us a zero y value: 9x2 + 12x + 4 = 0 9x2 + 6x + 6x + 4 = 0 3x(3x + 2) + 2(3x + 2) = 0 (3x + 2)(3x + 2) = 0 (3x + 2)2 = 0 3x + 2 = 0 3x = -2 x = - 2/3 So the x intercept is at -2/3 and the y intercept is at 4.
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