taking or showing extreme care about minute details
the ofrmula is x=-b/ab... trust me in in 8th grade taking a 11th grade course!!
This would be an upside-down parabola, with it's apex being at {0,0}. You can graph it by taking a few values of x (-2, -1, 0, 1, and 2 would be enough), finding their corresponding y positions(-4, -1, 0, -1, and -4 respectively), plotting them on the graph paper, and roughly sketching the curve that they follow.
You can find this answer by taking (545)^(1/3), which equals 8.16830917
That would be a quadratic expression which describes a parabola. You can find where it intersects the x-axis by solving it for zero: x2 + 2x - 7 = 0 x2 + 2x + 1 = 8 (x + 1)2 = 8 x + 1 = ± 2√2 x = -1 ± 2√2 This tells us that it intersects the x-axis at the points where x equals -1 + 2√2 and -1 - 2√2. If you'd like to find it's vertex, you can check that easily by taking it's derivative with respect to x and solving that for zero: y = x2 + 2x - 7 y' = 2x + 2 Let y' = 0: 0 = 2x + 2 2x = -2 x = -1 So we know that the vertex of this parabola is at the point where x = -1.
This is kind of obvious, a parabola going up and down wouldn't serve a purpose, since it's taking signals from a satellite in space. It goes left and right to get a better signal.
showing the people you have real money, that means taking it out of your merse (man purse) and showing it to them.
x2 + 12x = 0 is an equation that describes a parabola. This parabola would have a minimum value and no maximum. That minimum can be found by taking its derivative and solving for zero: y = x2 + 12x dy/dx = x + 12 0 = x + 12 x = -12 Then take that x value and plug it in to the original equation: y = (-12)2 + 12(-12) y = 144 - 144 y = 0 So the focal point of the parabola is at (-12, 0) If you want to factor it, that would come to: x(x + 12) = 0
A parabola You can find the peak of this parabola by taking it's derivative and finding the point where it's slope is equal to zero: y = 3x2 + x - 2 y' = 6x + 1 Let y' = 0 0 = 6x + 1 x = -1/6 Now find the y co-ordinate: y = 3(-1/6)2 + (-1/6) - 2 y = 3/18 - 1/6 - 2 y = -2 So this parabola's vertex will be located at the point (-1/6, -2).
taking or showing extreme care about minute details
the ofrmula is x=-b/ab... trust me in in 8th grade taking a 11th grade course!!
This is true. As it is the same number for A and B so taking C from one would be the same as taking C from the other.
You can work this out by taking the derivative of the equation, and solving for zero: y = x2 - 8x + 18 y' = 2x - 8 0 = 2x - 8 x = 4 So the vertex occurs where x is equal to 4. You can then plug that back into the original equation to get the y-coordinate: y = 42 - 8(4) + 18 y = 16 - 32 + 18 y = 2 So the vertex of the parabola occurs at the point (4, 2), leaving 2 as the answer to your question.
it means ur taking it to the next level or his just showing off
Well a photographer is a person taking the beauty and really showing it for what it really is.
This would be an upside-down parabola, with it's apex being at {0,0}. You can graph it by taking a few values of x (-2, -1, 0, 1, and 2 would be enough), finding their corresponding y positions(-4, -1, 0, -1, and -4 respectively), plotting them on the graph paper, and roughly sketching the curve that they follow.
You can calculate this by taking the derivative of the equation with respect to x, and solving it for a value of zero: y = x2 - 2x - 5 ∴ dy/dx = 2x - 2 Let dy/dx =0: 0 = 2x - 2 ∴ 2x = 2 ∴ x = 1 Now you can take that x value and plug it into the original equation to find it's y coordinate: y = 12 - 2(1) - 5 y = 1 - 2 - 5 y = -6 So the vertex of this parabola occurs at the point (1, -6).