set to 0
X^2 + 4X = 0
you must complete the square. halve the coefficient of the linear term (4X) and square it and add it to the other side.
(X + 2)^2 = 4
now subtract the 4 from both sides
(X + 2)^2 - 4 = 0
The graph of y = x2 (vertex (0,0) is shifted 2 units to the left, and 4 units down.
the vertex is....
(-2,-4)
my TI-84 confirms this answer
or
Since x = -4/2 = -2 is the equation of the axis of symmetry, and the vertex lies on it, then the x-coordinate of the vertex is -2 and the y-coordinate is f(-2).
f(-2) = (-2)2 + 4(-2) = 4 - 8 = -4
thus, the vertex is (-2, -4)
By inspection you should be able to see that this is a parabola with a vertex of this. (0, 0) There is no form for this function as there is no linear term.
The vertex of the positive parabola turns at point (-2, -11)
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
Do you have a specific vertex fraction? vertex = -b/2a wuadratic = ax^ + bx + c
By inspection you should be able to see that this is a parabola with a vertex of this. (0, 0) There is no form for this function as there is no linear term.
The vertex of the positive parabola turns at point (-2, -11)
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
The curve turns at a minimum: (2.5, -12)
The plural form of vertex is vertices or vertexes.
The difference between standard form and vertex form is the standard form gives the coefficients(a,b,c) of the different powers of x. The vertex form gives the vertex 9hk) of the parabola as part of the equation.
it will form a parabola on the graph with the vertex at point (0,0) and points at (1,1), (-1,1), (2,4), (-2,4)......
Do you have a specific vertex fraction? vertex = -b/2a wuadratic = ax^ + bx + c
The vertex form is y = (x - 4)2 + 13
The vertex form for a quadratic equation is y=a(x-h)^2+k.