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(0, 0), of course. No linear term.

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12y ago

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What is the vertex of y equals 3x to the second power?

(0, 0) of course! No linear term! Review you vertex manipulation again.


Where is the vertex coordinate of the parabola y equals x square -3x -10 located on the Cartesian plane?

7


Where is the vertex coordinate of the parabola y equals 24 -6x -3x squared when plotted on the Cartesian plane?

The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.


What is the vertex for y equals X raised to the second power?

The vertex is the origin, (0,0).


How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?

The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.


X to the second power times -3x?

x2 * -3x = -3x3


How do you know if the vertex is a minimum?

To determine if a vertex is a minimum in a quadratic function, you can analyze the coefficient of the quadratic term (the leading coefficient). If the coefficient is positive, the parabola opens upwards, indicating that the vertex is a minimum point. Additionally, you can use the second derivative test; if the second derivative at the vertex is positive, the vertex is confirmed as a minimum.


Find equation what parabola its vertex is 0 0 and it passes through point 2 12 express the equation in standard form?

Y=3x^2 and this is in standard form. The vertex form of a prabola is y= a(x-h)2+k The vertex is at (0,0) so we have y=a(x)^2 it goes throug (2,12) so 12=a(2^2)=4a and a=3. Now the parabola is y=3x^2. Check this: It has vertex at (0,0) and the point (2,12) is on the parabola since 12=3x2^2


What are the coordinates of the vertex of the graph of the equation y 3x squared - 12x - 5?

To find the vertex of the quadratic equation ( y = 3x^2 - 12x - 5 ), we can use the vertex formula ( x = -\frac{b}{2a} ), where ( a = 3 ) and ( b = -12 ). Plugging in the values, we get ( x = -\frac{-12}{2 \cdot 3} = 2 ). To find the corresponding ( y )-coordinate, substitute ( x = 2 ) back into the equation: ( y = 3(2)^2 - 12(2) - 5 = -29 ). Thus, the coordinates of the vertex are ( (2, -29) ).


What is the line of symmetry and the vertex when y equals 3x squared plus 2x minus 1?

y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)


What is factored form of 3x to the 2nd power plus 6x?

x(3x+6) or 3x(x+2). Id recomend the second one.


A base angle of an isosceles triangle is 9 degrees more than the vertex angle Find the vertex angle?

let the vertex angle be x degrees, then the base angle is x + 9 degrees. Since in a triangle the sum of the angle is 180 degrees, and the base angles in an isosceles triangle are congruent, we have: x + 2(x + 9) = 180 x + 2x + 18 = 180 3x + 18 = 180 subtract 18 to both sides 3x = 162 divide by 3 to both sides x = 54 Thus the vertex angle is 54 degrees.