To find the vertex of the quadratic equation ( y = x^2 - 4x + 3 ), you can use the vertex formula ( x = -\frac{b}{2a} ). Here, ( a = 1 ) and ( b = -4 ), so ( x = -\frac{-4}{2 \cdot 1} = 2 ). Substituting ( x = 2 ) back into the equation gives ( y = 2^2 - 4(2) + 3 = -1 ). Therefore, the vertex is at the point ( (2, -1) ).
3
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
y=4x-12-3 is the equation of a straight line. It does not have a vertex. Did you mean y=x squared - 12x - 3 ?
It is (1, 1).
Vertex implies quadratic equation. Y = X^2 + 4X + 7 set to 0 X^2 + 4X + 7 = 0 subtract 7 from each side X^2 + 4X = - 7 Now, complete the square. Halve the linear tern (4), square it and add it to both sides. X^2 + 4X + 4 = - 7 + 4 gather terms on the right and factor on the left (X + 2)^2 = - 3 (X + 2)^2 + 3 = 0 (-2,3) ------------------is the vertex
3
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
-4x + 4y = 1
y=4x-12-3 is the equation of a straight line. It does not have a vertex. Did you mean y=x squared - 12x - 3 ?
It is (1, 1).
Vertex implies quadratic equation. Y = X^2 + 4X + 7 set to 0 X^2 + 4X + 7 = 0 subtract 7 from each side X^2 + 4X = - 7 Now, complete the square. Halve the linear tern (4), square it and add it to both sides. X^2 + 4X + 4 = - 7 + 4 gather terms on the right and factor on the left (X + 2)^2 = - 3 (X + 2)^2 + 3 = 0 (-2,3) ------------------is the vertex
It is: y = -4x+12
4x-y+3 = 0 -y = -4x-3 y = 4x+3 Therefore: the slope is 4 and the y intercept is 3
The vertex of the positive parabola turns at point (-2, -11)
what is the slope of the line that has the equation 4x+2y=12?
Yes, y = 4x + 7 is a linear equation.
2x+4-x = 4x-5 2x-x-4x = -5-4 -3x = -9 x = 3