There are infinitely many possible rectangular shapes with an area of 6004 sq ft.
Let L be any length greater than sqrt(6004) ft
and let W = 6004/L
Then for each different value of L, there is a different rectangle that is L feet * W feet and its area will be L*W = L*6004/L = 6004 sq feet.
And that assumes the area is in the shape of a rectangle. It could be circular, or an ellipse, a triangle, or other polygon or even a random shape!
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
what is the length x width of a rectangle swimming pool that is 13300 sq ft
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
By multiplying its length to its width. Area= length x width
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
Area = Length * Width = 13 ft * 6 ft = 13*6 sq ft = 78 sq ft
what is the length x width of a rectangle swimming pool that is 13300 sq ft
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
Area = Length * Width 300 sq ft = L ft * W ft So W = 300/L ft
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
By multiplying its length to its width. Area= length x width
volume_cuboid = length × width × height = 4 ft × 2.3 ft × 5 ft = 46 cu ft surface_area_cuboid = 2 × (length × width + width × height + height × length) = 2 × (4 ft × 2.3 ft + 2.3 ft × 5 ft + 5 ft × 4 ft) = 2 × (9.2 sq ft + 11.5 sq ft + 20 sq ft) = 2 × 40.7 sq ft = 81.4 sq ft
Depends length-25ft width-10ft length - 125ft width - 2ft length - 50ft width- 5ft
length = 1380/width or width = 1380/length Unless a length or width is given it's impossible to give an accuratee answer.
You can't without one or the other. If you know length then width is the area divided by the length.
32 square feet. Multiply length by width.