10x2
24 meters
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
The rectangle is 6-ft long and 4-ft wide.
You divide the perimeter by the width and you get the lenght
10x2
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
Area = 8*24 =192 square feet Perimeter = 24+24+8+8 = 64 feet
24 meters
The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
Perimeter = 24 inches Area = 35 square inches
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
Let L be the length of the rectangle and W the width, then L = 2W - 3. The perimeter = 2L + 2W = 2(2W - 3) + 2W = 6W - 6 But the perimeter measures 18"so, 6W - 6 = 18 : 6W = 24 : W = 4 The width of the rectangle is 4".