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How do you find maximum or minimum of a function?
y=2x2-3x2-12x+5=0
3x2 plus 12x equals -1?
3x2 + 12x = - 1 ie 3x2 + 12x + 1 = 0 has no rational roots. The irrational roots are [-12 +/- sqrt(132)]/6 = -3.915 and -0.085
What is the minimum function value of f x 3x2 12x 5?
To find the minimum function value of ( f(x) = 3x^2 + 12x + 5 ), we can use the vertex formula for a quadratic function, which is given by ( x = -\frac{b}{2a} ). Here, ( a = 3 ) and ( b = 12 ), so ( x = -\frac{12}{2 \times 3} = -2 ). Substituting ( x = -2 ) back into the function, we get ( f(-2) = 3(-2)^2 + 12(-2) + 5 = 12 - 24 + 5 = -7 ). Thus, the minimum function value is ( -7 ).
How do you find the vertex of the parabola given by y equals -3x2 plus 12x-1?
-3x2+12x-1 = y Solve the quadratic equation when y = 0 by means of the quadratic equation formula which gives x values of 3.914854216 and 0.085145784. Add these values together and divide them by 2 which is 4/2 = 2 and this is the line symmetry of the parabola. Substitute 2 for x into the original equation to find the value of y: So the vertex is at (2, 11) Remember that the parabola has a maximum value because the coefficient of x2 is negative in other words it will face downwards.
What is the x intercept for y equals -3x2 plus 12x-9?
1 and 3
What is the x-coordinate of the of the vertex of y equals -3x2 plus 12x-5?
You can find the x-coordinate of it's vertex by taking it's derivative and solving for zero: y = -3x2 + 12x - 5 y' = -6x + 12 0 = -6x + 12 6x = 12 x = 2 Now that we have it's x coordinate, we can plug it back into the original equation to find it's y coordinate: y = -3x2 + 12x - 5 y = -3(2)2 + 12(2) + 5 y = -12 + 24 + 5 y = 17 So the vertex of the parabola y = -3x2 + 12x - 5 occurs at the point (2, 17).
How do you find maximum or minimum of a function?
y=2x2-3x2-12x+5=0
What is the equation for the axis of symmetry of the quadratic function f(x) 3x2 12x - 2?
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
3x2 plus 12x equals -1?
3x2 + 12x = - 1 ie 3x2 + 12x + 1 = 0 has no rational roots. The irrational roots are [-12 +/- sqrt(132)]/6 = -3.915 and -0.085
What is the GCF of 24x and 36x3?
GCF = 12x.24x = 2(12x)36x3 = 3x2(12x)
How can you tell if a equation is conditional inconsistent or identity?
3x2 -12x+24=-10x-20-3x2+6
What is the minimum function value of f x 3x2 12x 5?
To find the minimum function value of ( f(x) = 3x^2 + 12x + 5 ), we can use the vertex formula for a quadratic function, which is given by ( x = -\frac{b}{2a} ). Here, ( a = 3 ) and ( b = 12 ), so ( x = -\frac{12}{2 \times 3} = -2 ). Substituting ( x = -2 ) back into the function, we get ( f(-2) = 3(-2)^2 + 12(-2) + 5 = 12 - 24 + 5 = -7 ). Thus, the minimum function value is ( -7 ).
What is the discriminant of the equation -3x square - 12x plus 7 equals 8?
The equation is equivalent to: -3x2 - 12x - 1 = 0 [you could change signs to get 3x2 + 12x + 1 = 0 but that is not required] The discriminant is (-12)2 - 4*(-3)(-1) = 144 - 12 = 132
How do you find the vertex of the parabola given by y equals -3x2 plus 12x-1?
-3x2+12x-1 = y Solve the quadratic equation when y = 0 by means of the quadratic equation formula which gives x values of 3.914854216 and 0.085145784. Add these values together and divide them by 2 which is 4/2 = 2 and this is the line symmetry of the parabola. Substitute 2 for x into the original equation to find the value of y: So the vertex is at (2, 11) Remember that the parabola has a maximum value because the coefficient of x2 is negative in other words it will face downwards.
What is the line of symmetry for the graph of y equals -3x2 plus 12x - 11?
-2
What is the x intercept for y equals -3x2 plus 12x-9?
1 and 3
How many real solutions does the equation 3x2 12x 12 0 have?
If you mean: 3x^2+12x+12 = 0 then it has two equal solutions of -2
