x- and y-intercepts are point that lie on the axes, thus x-intercept point is (x, 0) and y-intercept point is (0, y).
So let y = 0. replace 0 for y into the equation and solve for x.
2(0) - 12x = -6
-12x = -6 divide by -12 both sides
x = 1/2
Thus, x-intercept point is (1/2, 0).
Let x = 0. replace 0 for x into the equation and solve for y.
2y - 12(0) = -6
2y = -6 divide by 2 both sides
x = -3
Thus, y-intercept point is (0, -3).
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If you mean: 8x-2y = 16 then the points are (2, 0) and (0, -8) which means x intercept is 2 and y intercept is -8
To find the x-intercept, plug 0 in for y: 0 = -x-1, so x = -1. To find the y-intercept, plug zero in for x: y=-0-1, so y = -1 The x-intercept is (0,-1) and the y-intercept is (-1,0)
usually the format is ax plus or minus ba is the slope and b is the y intercept
Slope is zero y-intercept is -7 there is no x-intercept for this equation
x - 3 = y-- At the x-intercept, y=0.x - 3 = 0x = 3The x-intercept is the point (3, 0).-- At the y-intercept, x=0.0 -3 = yy = -3The y-intercept is the point (0, -3).