Well, honey, the y-intercept is where the line crosses the y-axis, so when x=0, you solve for y. And the x-intercept is where the line crosses the x-axis, so when y=0, you solve for x. Just plug in the values and do the math, sweetie.
If you mean: 5x-2y = 20 then y = 2.5x-10 whereas the slope is 2.5 and the y intercept is -10 The x intercept will be at: (4, 0)
For the x intercept, put y = 0 in the equation. So 5x = 15 ie x = 3 So the intercept is (3,0)
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
Assume that the equation is y = 5x².To find the x-intercept of that equation, we need to set y = 0 and solve for x. Here:0 = 5x² which is equivalent to x² = 0.So x = 0. So the x-intercept is (0,0)
To find the x-intercept, set y equal to zero in the equation 5x + 2y = 20. Then solve for x: 5x + 2(0) = 20. Simplifying, 5x = 20. Dividing both sides by 5, x = 4. Therefore, the x-intercept is (4, 0).
If you mean: 5x-2y = 20 then y = 2.5x-10 whereas the slope is 2.5 and the y intercept is -10 The x intercept will be at: (4, 0)
Get in slope intercept form.5X - 2Y = 20- 2Y = - 5X + 20Y = (5/2)X - 10===============zero out the Y(5/2)X - 10 = 0(5/2)X = 10X = 4=====(4, 0) is the intercept point for X
For the x intercept, put y = 0 in the equation. So 5x = 15 ie x = 3 So the intercept is (3,0)
5x - 2y = 20The x-intercept of a line is the point where its y-value is 0. When y=0, we get 5x = 20, or x=4. This means the coordinates of the x-intercept on this line are (4,0).
(5,-12)
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
X intercept is where it intersects the X-axis, which is where y = 0. So set y=0 in the equation, and solve for x. 5x - 2(0) = 10 --> 5x = 10 --> x = 2. So the point (2,0) is where the x-intercept is.
Assume that the equation is y = 5x².To find the x-intercept of that equation, we need to set y = 0 and solve for x. Here:0 = 5x² which is equivalent to x² = 0.So x = 0. So the x-intercept is (0,0)
To find the x-intercept, set y equal to zero in the equation 5x + 2y = 20. Then solve for x: 5x + 2(0) = 20. Simplifying, 5x = 20. Dividing both sides by 5, x = 4. Therefore, the x-intercept is (4, 0).
5x - 6 = -25x = 4x = 4/5, the intercept
The point (0, -5) is the y-intercept (x = 0)
5x - 2y = 05x - 5x - 2y = 0 - 5x-2y = - 5x(-2y)/-2 = (-5x)/-2y = (5/2)x where the slope is 5/2 and the y-intercept is 0.