The probability of ac and bc is 1/5.
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
AC = sqrt(AB^2+BC^2) other wise known as a^2+b^2=c^2. Therefore AC is around 51.739
associative? single replacement
hello
A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.
The probability of ac and bc is 1/5.
associative? single replacement
a+bc --> ac+b
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
A+bc---> b+ac
AC=5 AB=8 A=1 B=8 C=5 BC=40
The point B lies between points A and C is the distances AB, BC and AC are related by:AB + BC = AC.
A+bc---> b+ac
(a + b)(b + c)
If you mean (a-b+c)^2, then... a^2 - ab + ac - ab + b^2 - bc + ac - bc + c^2 = a^2 + b^2 + c^2 - 2ab + 2ac - 2bc.
If a < b, and c is positive, then ac < bcIf a < b, and c is negative, then ac > bc(inequality swaps over!)