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Possibly distribution, as it seems that a c was distributed to the a and the b.

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11y ago

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A and b are events with complements ac and bc and if p of a is point 3 and p of b is point 5 find p of ac and bc?

The probability of ac and bc is 1/5.


How is a plus b over a minus b equals c plus d over c minus d?

(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c


If a plus b plus c equal 12 and a square plus b square plus c square equal 64 find the value of Ab plus BC plus AC?

We can use the identity ((a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + ac + bc)). Given that (a + b + c = 12) and (a^2 + b^2 + c^2 = 64), we can substitute these values into the identity: [ 12^2 = 64 + 2(ab + ac + bc). ] Calculating (12^2) gives us 144, so: [ 144 = 64 + 2(ab + ac + bc). ] Subtracting 64 from both sides gives us: [ 80 = 2(ab + ac + bc). ] Dividing by 2, we find: [ ab + ac + bc = 40. ] Thus, the value of (ab + ac + bc) is 40.


If AB is 34 and BC is 89nwhat is AC?

AC = sqrt(AB^2+BC^2) other wise known as a^2+b^2=c^2. Therefore AC is around 51.739


What is the formula to find AC?

To find the length of side AC in a triangle, you can use the Law of Cosines if you know the lengths of the other two sides (AB and BC) and the included angle (∠B). The formula is: [ AC^2 = AB^2 + BC^2 - 2 \times AB \times BC \times \cos(\angle B) ] After calculating AC², take the square root to find AC. If you have a right triangle, you can simply use the Pythagorean theorem: [ AC = \sqrt{AB^2 + BC^2} ] (assuming AC is the hypotenuse).