Possibly distribution, as it seems that a c was distributed to the a and the b.
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The probability of ac and bc is 1/5.
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
AC = sqrt(AB^2+BC^2) other wise known as a^2+b^2=c^2. Therefore AC is around 51.739
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associative? single replacement