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Factors are (x + 1)(x + 3) so x = -1 or -3.
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The factors given above are correct.
But the solution offered above is correct, only if
x2 + 4x + 3 = 0.
If the given quadratic function is equated to anything other than zero, then the solution will also be something else.
Example:
x2 + 4x + 3 = 15 gives
x2 + 4x - 12 = 0, whence,
(x - 2 )(x + 6) = 0; and
it is evident that x = 2 or -6 is the desired solution.
In other words, if you substitute either 2 or -6 for x in the equation
x2 + 4x + 3 = 15,
then, that equation becomes a true statement. Test it, and see!
On the other hand, x = -1 or -3 makes the equation
x2 + 4x + 3 = 0
a true statement.
The moral to remember is that expressions, such as the asker gave above, have factors; but only equations have solutions.
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What is x2 plus 4x plus 4 equals 25?
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
Solve x2 plus 4x plus 3 equals 0?
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
2x equals x2 plus 4x-3?
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
What are solutions to the equation x2 plus 4x-9 equals 5x plus 3?
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
X2 plus 4x - 9 equals 5x plus 3?
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
