x3+640=0?
If that's the case, then you first want to move the 640 to the other side.
x3=-640
Then you take the cube root of -640 to find what x is. Or you can also write it as x=(-640) to the 1/3 power.
x=(-640)1/3
Which is equal to 4*101/3 or ≈(-8.618).
Chat with our AI personalities
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
It is x = -5
x3 - 11x2 + 18x = 0x (x2 - 11x + 18) = 0 . . . . x = 0 is a root.x (x - 9) ( x - 2) = 0 . . . . x = 9 and x = 2 are roots.X = 0, 2, 9
x2-x3+2x = 0 x(-x2+x+2) = 0 x(-x+2)(x+1) = 0 Points of intersection are: (0, 2), (2,10) and (-1, 1)
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.