Guessing they are powers and no operational symbol is between the two (ie a multiplication is assumed), then:
x6 x2 = x6 + 2 = x8
Otherwise, re-ask with words for missing symbols, eg "what is x to the power 6 plus x to the power 2 simplified"
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There are infinite varieties of dimensions as 4'x6' , 3'x8', 12'x2', ..., etc
The new mean would be 7. The mean is the average of the data. (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10=21 [(x1/3)+(x2/3)+(x3/3)+(x4/3)+(x5/3)+(x6/3)+(x7/3)+(x8/3)+(x9/3)+(x10/3)]/10=? [(1/3)(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)]/10=? [(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10]/3= 21/3=7
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)
x^2+x^2=2x^2
Cos(x) = 1 - x2/2! + x4/4! - x6/6! + ... where x is measured in radians